a generalizing direction


we are ending realized that as 2n-1 divides B_n={2n\choose n}, then

{D_n}^{-1}=\frac{2n-1}{B_n}

indicates a rute of discoveries…

as sided to the catalanization one: {C_n}^{-1}=\frac{n+1}{B_n}.

Zum beispiel: Enter

series(4 (4-x)^(3/2)-12 x sqrt(4-x) – 12 x^(3/2) arctan(sqrt( x/(4-x) )))/(4-x)^(5/2)

in a wolframalpha window.

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